Combinations vs Permutations: When Order Matters
Published 7/28/2025 · 3 min read · Everyday calculators
A permutation counts ordered arrangements, while a combination counts unordered selections. Use permutations (nPr = n! / (n − r)!) when the sequence matters, such as ranking finishers in a race. Use combinations (nCr = n! / (r! · (n − r)!)) when only the group matters, such as choosing a committee. For the same n and r, there are always more permutations than combinations, because each combination can be reordered in r! ways.
The difference between combinations and permutations comes down to one question: does order matter? Learn the nCr and nPr formulas with clear worked examples.
The one question that decides which to use
Before reaching for a formula, ask whether reordering the same items produces a new outcome. If it does, order matters and you need a permutation. If reordering changes nothing meaningful, order is irrelevant and you need a combination.
A quick test: a race podium is a permutation because gold, silver, and bronze are distinct positions. A handful of lottery numbers is a combination because the ticket wins regardless of the order in which the balls are drawn.
The two formulas side by side
The permutation formula is nPr = n! / (n − r)!, where n is the number of available items and r is how many you arrange. The combination formula divides that result by r! to cancel the orderings: nCr = n! / (r! · (n − r)!). The extra r! in the denominator is exactly why combinations are always the smaller count.
Note that n! (n factorial) means the product 1 × 2 × ... × n, and 0! is defined as 1. That convention keeps the formulas working when r equals n, where there is exactly one way to arrange or select everything.
A worked example with the same numbers
Take 5 people and pick 3. The permutations are nPr = 5! / (5 − 3)! = 120 / 2 = 60 ordered line-ups. The combinations are nCr = 5! / (3! · 2!) = 120 / (6 × 2) = 10 unordered groups. The ratio 60 / 10 = 6 is exactly 3!, confirming that each group of 3 can be ordered in 6 ways.
This relationship generalizes: nPr = nCr × r!. Whenever you already have a combination count, multiply by r! to get the permutation count, and divide by r! to go the other way.
Worked with our own calculator
Combination calculator (nCr)
Given
- n (total)
- 20
- r (chosen)
- 6
Result
- nCr
- 38,760
These figures are produced by the calculator below, not typed in by hand — they are recomputed whenever the tool changes.
Run it on your own figures →Frequently asked questions
- Is a lock combination really a combination?
- No, it is mathematically a permutation. On a lock, 1-2-3 and 3-2-1 open different locks, so order matters and the correct term is permutation despite the everyday name.
- Which is always larger for the same n and r?
- Permutations are always at least as large, because nPr = nCr × r!. They are equal only when r is 0 or 1, since 0! and 1! both equal 1.
- Does repetition change the formulas?
- Yes. The formulas here assume each item is used at most once (no repetition). If items can repeat, you use different formulas, such as n^r for ordered selections with repetition.
- How is nCr related to Pascal's triangle?
- Each entry in Pascal's triangle is a combination count: the value in row n, position r, is nCr. That is why the triangle's numbers appear as the coefficients when you expand (a + b)^n.
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