The Outer Tenth of a Disc Is a Fifth of Its Area
Published 10/20/2026 · 4 min read · Everyday calculators
Marco Bianchi — Home, DIY & motoring writer at OneKitly
Renovation · Materials
Checked against 2 sources
The area of a ring is π times the outer radius squared minus π times the inner radius squared, and because both terms are squared the outer part of a disc counts for far more than its width suggests. A ring from radius 9 to radius 10 measures 59.69 square units against a full disc of 314.16 — nineteen per cent of the area from a rim one tenth as wide as the radius. Go further in and the effect reverses: everything inside half the radius is only a quarter of the area, so the outer half holds three quarters of it. The same arithmetic sizes the metal in a pipe: a 60 mm tube with a 3 mm wall has 537 square millimetres of steel around a 2,290 mm² bore.
A ring from radius 9 to 10 covers 59.7 square units of a 314.2 disc — 19 %, from a rim one tenth as wide as the radius. A 60 mm pipe with a 3 mm wall obeys the same arithmetic.
Doubling the wall does not double the metal
Taking the same 60 mm tube from a 3 mm wall to a 6 mm one lifts the steel cross-section from 537 to 1,018 square millimetres — a factor of 1.90, not 2. The reason is that the second three millimetres sit further in, on a smaller circumference, so each one contributes less area than the one outside it. Anyone estimating the weight of tube stock by scaling the wall thickness is therefore over-ordering slightly, and anyone estimating a thin-wall tube by the same shortcut is close enough that the error never shows. The thicker the wall relative to the diameter, the worse the shortcut gets.
Same shape, opposite conclusion for flow
The bore is the same square law read the other way, and it is why a modest increase in pipe diameter buys so much capacity. Going from a 27 mm bore to a 30 mm one — eleven per cent wider — raises the cross-section by twenty-three per cent, and the flow at a given pressure drop rises faster still, because the fluid near the centre moves faster than the fluid near the wall. That is the argument for oversizing a run of pipe rather than adding a pump, and it also explains why a build-up of scale that narrows a pipe by a couple of millimetres costs far more flow than the thickness suggests.
| Ring | Area | Share of the disc |
|---|---|---|
| 9 to 10 | 59.69 | 19 % |
| 6 to 10 | 201.06 | 64 % |
| 5 to 10 | 235.62 | 75 % |
Worked with our own calculator
Annulus (ring) area calculator
Given
- Outer radius
- 20
- Inner radius
- 12
Result
- Area
- 804.248
These figures are produced by the calculator below, not typed in by hand — they are recomputed whenever the tool changes.
Run it on your own figures →Frequently asked questions
- Is a running track lane the same problem?
- Related, but the quantity that matters there is the circumference rather than the area. Each lane outward adds two π times the lane width to the lap distance, and that increment is the same whatever the radius — which is why the staggered start lines on a track are evenly spaced and why the stagger does not grow for the outer lanes. Area is what you need for surfacing material and paint; circumference is what you need for fairness. Confusing the two is the fastest way to order the right amount of tarmac and the wrong starting positions.
- How do I get the area if I only have diameters?
- Halve them first and keep halving them first. Pipes, washers and tubes are almost always specified by diameter, and dropping the halving step multiplies the answer by four rather than by two — a mistake large enough to be obvious in a total and small enough to survive a quick glance at one figure. A tube described as 60 by 3 usually means a 60 mm outside diameter with a 3 mm wall, so the two radii are 30 and 27, not 60 and 57. When a supplier's table gives a mass per metre, that is the fastest cross-check available: work out the annulus, multiply by the density, and see whether the two agree.
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